Find the dimensions of the regular corral split into 2 pens of the same size producing the greatest possible enclosed area given 900 feet of fencing.

Answer:Length = 225 ftWidth = 150 ftStep-by-step explanation:If L is the length and W is the width, then:900 = 2L + 3WA = LWSolve for W in the first equation:3W = 900 − 2LW = 300 − ⅔ LSubstitute into the area equation:A = L (300 − ⅔ L)A = 300L − ⅔ L²Use calculus to find dA/dL and set to 0, or use the formula for vertex of a parabola.Using calculus:dA/dL = 300 − 4/3 L0 = 300 − 4/3 LL = 225Using vertex formula:L = -b / (2a)L = -300 / (-4/3)L = 225Find the width:W = 300 − ⅔ LW = 150You got the right answers, but the problem says to assume that the length is greater than the width.